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-0.5x^2+0.8x+32.8=0
a = -0.5; b = 0.8; c = +32.8;
Δ = b2-4ac
Δ = 0.82-4·(-0.5)·32.8
Δ = 66.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.8)-\sqrt{66.24}}{2*-0.5}=\frac{-0.8-\sqrt{66.24}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.8)+\sqrt{66.24}}{2*-0.5}=\frac{-0.8+\sqrt{66.24}}{-1} $
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